1.875x^2-12x+8=0

Solution for 1.875x^2-12x+8=0 equation:

1.875x^2-12x+8=0

a = 1.875; b = -12; c = +8;
Δ = b2-4ac
Δ = -122-4·1.875·8
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{21}}{2*1.875}=\frac{12-2\sqrt{21}}{3.75}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{21}}{2*1.875}=\frac{12+2\sqrt{21}}{3.75}
$